An object is projected vertically upwards. Its height, h m, at time t seconds is given by \(h = 20t - \frac{3}{2}t^{2} - \frac{2}{3}t^{3}\). Find 

(a) the time at which it is momentarily at rest  (b) correct to two decimal places, the maximum height reached by the object.

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KillerBobo15
5 years ago

b is wrong the answer is approx 30.21 m. It is 50 - 75/8 - 125/12

packo
1 year ago

wrong answer

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