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Find the coordinates of the centre of the circle \(4x^{2} + 4y^{2} - 5x +...

Further Mathematics
WAEC 2006

Find the coordinates of the centre of the circle \(4x^{2} + 4y^{2} - 5x + 3y - 2 = 0\).

  • A. \((\frac{-5}{4}, \frac{3}{4})\)
  • B. \((\frac{3}{8}, -\frac{5}{8})\)
  • C. \((\frac{5}{8}, -\frac{3}{8})\)
  • D. \((\frac{5}{4}, -\frac{3}{4})\)
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Correct Answer: Option C
Explanation

Equation : \((x - a)^{2} + (y - b)^{2} = r^{2}\)

Expanding : \(x^{2} + y^{2} - 2ax - 2by + a^{2} + b^{2} = r^{2}\)

Given, \(4x^{2} + 4y^{2} - 5x + 3y - 2 = 0\)

Divide through by 4 to make the coefficient of \(x^{2}\) and \(y^{2}\) to be 1.

\(x^{2} + y^{2} - \frac{5}{4}x + \frac{3}{4}y - \frac{1}{2} = 0\)

Comparing, \(2a = \frac{5}{4} \implies a = \frac{5}{8}\)

\(2b = -\frac{3}{4} \implies b = -\frac{3}{8}\)

\((a, b) = (\frac{5}{8}, -\frac{5}{8})\)


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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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