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A.
\(2^{-n}\)
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B.
\(2^{1 - n}\)
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C.
\(2^{n}\)
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D.
\(2^{n + 1}\)
Correct Answer: Option A
Explanation
\(8^{n} \times 2^{2n} \div 4^{3n} = 2^{3n} \times 2^{2n} \div 2^{6n}\)
\(2^{2n + 3n - 6n}\)
= \(2^{-n}\)
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