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\(P = {x : 1 \leq x \leq 6}\) and \(Q = {x : 2...

Further Mathematics
WAEC 2006

\(P = {x : 1 \leq x \leq 6}\) and \(Q = {x : 2 < x < 9}\) where \(x \in R\), find \(P \cap Q\).

  • A. \({x : 2 \leq x \leq 6}\)
  • B. \({x : 2 \leq x < 6}\)
  • C. \({x : 2 < x < 6}\)
  • D. \({x : 2 < x \leq 6}\)
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Correct Answer: Option D
Explanation

\(P = {x : 1 \leq x \leq 6}\) and \(Q = {x : 2 < x < 9}\) where \(x \in R\), find \(P \cap Q\).

P = { 1, 2, 3, 4, 5, 6}

Q = {3, 4, 5, 6, 7, 8}

\(P \cap Q\). = { 3, 4, 5, 6}

Therefore, P ∩ Q = {x: 2 < x ≤ 6}


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