Three forces \(F_{1} = (8 N, 300°), F_{2} = (6 N, 090°)\) and \(F_{3} = (4 N, 180°)\) act on a particle. Find the vertical component of the resultant force.
The vertical component = \(8 \sin 300 + 6 \sin 90 + 4 \sin 180\)
= \(-4\sqrt{3} + 6 + 0 \)
= \((6 - 4\sqrt{3}) N\)
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