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The coefficient of the 5th term in the binomial expansion of \((1 + kx)^{8}\), in...

Further Mathematics
WAEC 2008

The coefficient of the 5th term in the binomial expansion of \((1 + kx)^{8}\), in ascending powers of x is \(\frac{35}{8}\). Find the value of the constant k.

  • A. 2
  • B. \(\frac{1}{2}\)
  • C. \(-\frac{1}{2}\)
  • D. -2
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Correct Answer: Option B
Explanation

\((1 + kx)^{8} = ^{8}C_{0}(1^{8})(kx)^{0} + ^{8}C_{1}(1^{7})(kx)^{1} + ...\)

The 5th term = \(^{8}C_{5 - 1}(1^{4})(kx)^{4}\)

= \(^{8}C_{4} (kx)^{4}\)

\(\implies 70k^{4} = \frac{35}{8}\)

\(k^{4} = \frac{\frac{35}{8}}{70}\)

\(k^{4} = \frac{1}{16}\)

\(k = \frac{1}{2}\)


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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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