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A body is acted upon by forces \(F_{1} = (10 N, 090°)\) and \(F_{2} =...

Further Mathematics
WAEC 2009

A body is acted upon by forces \(F_{1} = (10 N, 090°)\) and \(F_{2} = (6 N, 180°)\). Find the magnitude of the resultant force.

  • A. 11.6 N
  • B. 11.7 N
  • C. 11.8 N
  • D. 11.9 N
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Correct Answer: Option B
Explanation

\(F = F \cos \theta i + F \sin \theta j\) (Resolving F into its components)

\(F_{1} = (10 N, 090°) = 10 \cos 90 i + 10 \sin 90 j\)

= \(10 j\)

\(F_{2} = (6 N, 180°) = 6 \cos 180 i + 6 \sin 180 j\)

= \(-6 i\)

\(R = - 6 i + 10 j\)

\(|R| = \sqrt{(-6)^{2} + (10)^{2}}\)

= \(\sqrt{136}\)

= 11.7 N


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