Given \(\sin \theta = \frac{\sqrt{3}}{2}, 0° \leq \theta \leq 90°\), find \(\tan 2\theta\) in surd form.
\(\sin \theta = \frac{\sqrt{3}}{2} \implies opp = \sqrt{3}; hyp = 2\)
\(adj^{2} = 2^{2} - (\sqrt{3})^{2} = 1 \implies adj = 1\)
\(\cos \theta = \frac{1}{2}\)
\(\sin 2\theta = \sin (180 - \theta) = \sin \theta = \frac{\sqrt{3}}{2}\)
\(\cos 2\theta = \cos (180 - \theta) = -\cos \theta = -\frac{1}{2}\)
\(\tan 2\theta = \frac{\sin 2\theta}{\cos 2\theta} = \frac{\frac{\sqrt{3}}{2}}{-\frac{1}{2}}\)
= \(- \sqrt{3}\)
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}