The functions f and g are defined on the set, R, of real numbers by \(f : x \to x^{2} - x - 6\) and \(g : x \to x - 1\). Find \(f \circ g(3)\).
\(f : x \to x^{2} - x - 6\); \(g : x \to x - 1\)
\(g(3) = 3 - 1 = 2\)
\(f(g(3)) = f(2) = 2^{2} - 2 - 6 = 4 - 2 - 6 = -4\)
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