Find the standard deviation of the numbers 3,6,2,1,7 and 5.
\(\bar{x} = \frac{24}{6} = 4\)
\(S.D = \sqrt{\frac{\sum (x - \bar{x})^{2}}{n}}\)
= \(\sqrt{\frac{28}{6}} = \sqrt{4.667} = 2.16\)
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