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Solve \(9^{2x + 1} = 81^{3x + 2}\)

Further Mathematics
WAEC 2011

Solve \(9^{2x + 1} = 81^{3x + 2}\)

  • A. \(\frac{-3}{4}\)
  • B. \(\frac{-2}{3}\)
  • C. \(\frac{4}{5}\)
  • D. \(\frac{3}{2}\)
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Correct Answer: Option A
Explanation

\(9^{2x + 1} = 81^{3x + 2}\)

\(9^{2x + 1} = (9^{2})^{3x + 2}\)

\(9^{2x + 1} = 9^{6x + 4}\)

Equating powers, 

\(2x + 1 = 6x + 4 \implies -3 = 4x\)

\(\therefore x = \frac{-3}{4}\)


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Project Topics and Materials, Post-UTME past questions - Download now or upload yours to get paid
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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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NECO June/July 2024 - Get offline past questions & answers - Download objective & theory, all in one app 48789