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If \(y^{2} + xy - x = 0\), find \(\frac{\mathrm d y}{\mathrm d x}\).

Further Mathematics
WAEC 2011

If \(y^{2} + xy - x = 0\), find \(\frac{\mathrm d y}{\mathrm d x}\).

  • A. \(\frac{1 - y}{2y}\)
  • B. \(\frac{1 - 2y}{x}\)
  • C. \(\frac{1 - y}{x + 2y}\)
  • D. \(\frac{1}{x + 2y}\)
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Correct Answer: Option C
Explanation

Given \(y^{2} + xy - x = 0\)

Using the method of implicit differentiation, we have

\(2y\frac{\mathrm d y}{\mathrm d x} + x\frac{\mathrm d y}{\mathrm d x} + y - 1 = 0\)

\(\frac{\mathrm d y}{\mathrm d x}(2y + x) = 1 - y\)

\(\frac{\mathrm d y}{\mathrm d x} = \frac{1 - y}{x + 2y}\)


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Project Topics and Materials, Post-UTME past questions - Download now or upload yours to get paid
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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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