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Differentiate \(\frac{x}{x + 1}\) with respect to x.

Further Mathematics
WAEC 2012

Differentiate \(\frac{x}{x + 1}\) with respect to x.

  • A. \(\frac{1}{x + 1}\)
  • B. \(\frac{1}{(x + 1)^{2}}\)
  • C. \(\frac{1 - x}{x + 1}\)
  • D. \(\frac{1 - x}{(x + 1)^{2}}\)
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Correct Answer: Option B
Explanation

\(y = \frac{x}{x + 1}\)

Using quotient rule because the function is of the form \(\frac{u(x)}{v(x)}\)

\(\frac{\mathrm d y}{\mathrm d x} = \frac{v\frac{\mathrm d u}{\mathrm d x} - u\frac{\mathrm d v}{\mathrm d x}}{v^{2}}\)

\(\frac{\mathrm d y}{\mathrm d x} = \frac{(x + 1) . 1 - x . 1}{(x + 1)^{2}}\)

= \(\frac{1}{(x + 1)^{2}}\)


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