Forces 50N and 80N act on a body as shown in the diagram. Find, correct to the nearest whole number, the horizontal component of the resultant force.
Given a force F, the horizontal component = \(F\cos \theta\)
R = \(-50\cos 30 + 80\cos 45\)
= \(-50(\frac{\sqrt{3}}{2}) + 80(\frac{\sqrt{2}}{2})\)
= \( -25\sqrt{3} + 40\sqrt{2} = -43.30 + 56.67 \)
= \(13.37N \approxeq 13N\)
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