A ball is thrown vertically upwards with a velocity of 15\(ms^{-1}\). Calculate the maximum height reached. \([g = 10ms^{-2}]\)
Maximum height (H) = \(\frac{u^{2}}{2g}\)
= \(\frac{15^{2}}{2 \times 10} = \frac{225}{20}\)
= \(11.25m\)
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