Correct Answer: Option D

Explanation

\((x - \frac{1}{x})^{2} = x^2 - 2 + \frac{1}{x^2}\)

\(\int (x^2 + \frac{1}{x^2} - 2) \mathrm {d} x\)

= \(\int (x^2 + x^{-2} - 2) \mathrm {d} x\)

= \(\frac{x^3}{3} - 2x - \frac{1}{x}\)

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