A 24N force acts on a body such that it changes its velocity from 5m/s to 9m/s in 2 secs.If the body is travelling in a straight line, calculate the distance covered in the period.
\(a = \frac{v - u}{t} = \frac{9 - 5}{2} = 2 ms^{-2}\)
\(s = ut + \frac{1}{2}at^{2} = 5(2) + \frac{1}{2}(2 \times 2^{2})\)
= \(14m\)
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