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Given n = 3, evaluate \(\frac{1}{(n-1)!} - \frac{1}{(n+1)!}\)

Further Mathematics
WAEC 2016

Given n = 3, evaluate \(\frac{1}{(n-1)!} - \frac{1}{(n+1)!}\)

  • A. \(12\)
  • B. \(2\frac{1}{2}\)
  • C. \(2\)
  • D. \(\frac{11}{24}\)
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Correct Answer: Option D
Explanation

n = 3, \(\frac{1}{(n-1)!} - \frac{1}{(n+1)!} = \frac{1}{(3-1)!} - \frac{1}{(3+1)!}\)

= \(\frac{1}{2} - \frac{1}{24} = \frac{12 -1}{24}\)

= \(\frac{11}{24}\)


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