Correct Answer: Option D

Explanation

Let the power of \(2x^{2}\) be t and the power of \(\frac{1}{x} \equiv x^{-1}\) = 9 - t.

\((2x^{2})^{t}(x^{-1})^{9 - t} = x^{0}\)

Dealing with x alone, we have

\((x^{2t})(x^{-9 + t}) = x^{0} \implies 2t - 9 + t = 0\)

\(3t - 9 = 0 \therefore t = 3\)

The binomial expansion is then,

\(^{9}C_{3} (2x^{2})^{3}(x^{-1})^{6} = \frac{9!}{(9-3)! 3!} \times 2^{3}\)

= 84 x 8

= 672

• Alright guys, hopefully we all used today to catch up on some things we had forgotten. Math tomorrow... How we... Answer this

  27 Answers   ·   Mathematics   ·   4 days ago
• A man drove a car from his office o 12okm on a bearing of 135° and then drove for another... Answer this

  0 Answers   ·   Mathematics   ·   2 hours ago
• list the importance of water to crops? Answer this

  3 Answers   ·   3 years ago