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Find the stationary point of the curve \(y = 3x^{2} - 2x^{3}\).

Further Mathematics
WAEC 2018

Find the stationary point of the curve \(y = 3x^{2} - 2x^{3}\).

  • A. (1, 0)
  • B. (-1, 0)
  • C. (1, 1)
  • D. (-1, -1)
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Correct Answer: Option A
Explanation

\(y = 3x^{2} - 2x^{3}\)

\(\frac{\mathrm d y}{\mathrm d x} = 6x - 6x^{2} = 0 \implies 6x(1 - x) = 0\)

\(x = 0, 1\), when x = 1, y = 0.

when x = 1, y = 0.

The stationary point is (1, 0)


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