Given that \(f(x) = 5x^{2} - 4x + 3\), find the coordinates of the point where the gradient is 6.
\(f(x) = 5x^{2} - 4x + 3\)
\(f'(x) = 10x - 4 = 6 \implies 10x = 10; x=1\)
When x = 1, f(x) = y = \(5(1^{2}) - 4(1) + 3 = 4\)
The coordinates are (1,4)
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