In a firm, three employees earns N5,500 each, four earn N3,300 each, two earns N5,000 each and one earn N7,000. The mean income of the employees is?
Three employees earns N5,500 each = 3 x 5,500 = 16,500
Four earn N3,300 each, = 4 x 3,300 = 13, 200
Two earns N5,000 each = 2 x 5000 = 10000
One earn N7,000 = 1 x 7000 = 7000
Total income = 46,700
Number of employees = 3 + 4 + 2 + 1 = 10
The mean income of the employees = \(\frac{\text{total income}}{\text{No of employees}}\) = \(\frac{46,700}{10}\) = N4,670
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}