Convert \(47_8\) to its binary equivalent.
Convert to base 10 first.
\(47_8\) = 4 x \(8^1\) + 7 x \(8^0\) = \(39_{10}\)
Then convert \(39_{10}\) to base 2 as follows
Therefore \(47_8\) is equivalent to \(100111_2\)
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