Which of the following gases will diffuse fastest when passed through a porous plug?
[H = 1, C = 12, N = 14, O = 16]
Propane
Oxygen
Methane
Ammonia
Explanation
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Propane=C3H8
Molar Mass Of Propane=3*12+8=32
Oxygen is a diatomic gas therefore 02=16*2=32
Methane is CH4 Therefore The Molar Mass=12+1*4=16
Ammonia(NH3)=14+1*3=17
Therefore The Correct Answer Is C Because The Lower The RMM of a gas the faster the rate of diffusion
Propane(C3H8) = 56
Oxygen (O2) = 32
Methane(CH4) = 16
Ammonia (NH3) = 17...
The rate of diffusion will be higher in the gas with the lowest RMM.. METHANE
d gas wit d lowest RMM wil always have d highest rate of difusion.e.g take propane n methane:
RMM 4 propane=C3H8 (3*12 + 8*1)=44
RMM 4 methane=CH2 (12 + 2*1)=14
V.D 4 Propane=RMM/2 =22
V.D 4 Methane=RMM/2= 7
Since rate of difusion of a gas is inversely proportional 2 d sq root of its v.d,
mathematicly,we al knw dt an increased vapour density brings about a lesser rate of difusion,ceteris paribus...wich makes methane come up wit d higher rate of difusion comparing it wt propane.GUDLUK GYZ
d ans is c.methane has lowest RMM which 16.oxygen is 32 wen single i.e O2.Ammonia 17 nd propane is 44.gbam*
According to Graham's Law of Diffusion:
Rate of diffusion ∝ 1/√Molecular weight
The molecular weights of the given gases are:
A. Propane (C3H8) = 44 g/mol
B. Oxygen (O2) = 32 g/mol
C. Methane (CH4) = 16 g/mol
D. Ammonia (NH3) = 17 g/mol
The gas with the lowest molecular weight will diffuse the fastest:
C. Methane (CH4) = 16 g/mol
So, Methane will diffuse the fastest.
Here is an explanation:
By finding the molar masses of each substance provided in the question the molar masses of propane, oxygen, methane, and ammonia will be 44,36,14,and,18 respectively.
The lower the molar mass the higher the rate of diffusion and that will be your answer
the answer is methane because lower the relative molecular mass, the higher thae rate of diffusion
