The electron configuration of element Y is 1S\(^2\)2S\(^2\)2P\(^6\)3S\(^2\)3P\(^4\). Y, therefore,

a

has mass number of 16

b

has three unpaired electron

c

belongs to period 4

d

belongs to group VI

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Explanation

Correct Option
d

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Discussions (5)

Excuse me why don't you guys provide answers to this question

Anyways option D is correct

Kaosideya
2 months ago

Option D is correct. the element is sulphur which is in group 6

Purity252
2 months ago

thanks for the clarification

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