The percentage by mass of water in Na\(_2\)CO\(_3\).10H\(_2\)O is [ Na\(_2\)CO\(_3\).10H\(_2\)O = 286, H\(_2\)O = 18 ]
a
68.4%
b
62.9%
c
9.7%
d
6.3%
Explanation
Correct Option
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Temitojo
2 months ago
For Na2CO3.10H20
Total Molar mass = 286g/mol
water part = 10*18 =180
The Percentage of water = 180/286*100=62.9%
Option B
