The number of moles of KOH present in 200cm\(^3\) of 5.6 g dm\(^{-3}\) solution is [KOH = 56 g mol\(^{-1}\)]
a
2.01
b
1.12
c
0.02
d
0.01
Explanation
Correct Option
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The number of moles of KOH present in 200cm\(^3\) of 5.6 g dm\(^{-3}\) solution is [KOH = 56 g mol\(^{-1}\)]
2.01
1.12
0.02
0.01
No video available
