Consider the following equation H2O + 2Fe2+ + Cl2 ↔ 2Fe3+ + 2Cl- + H2O. Which behaves as an oxidizing agent?
Fe2+
Cl2
Fe3+
Cl-
H2O
Explanation
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Now according to the reactions,
2Fe²⁺ on the left hand side and 2Fe³⁺ on the right.
2Fe²⁺ ------------> 2Fe³⁺ + 2e⁻
loss of electron is oxidation.
while for 2Cl⁻ on the right and Cl₂ on the left. The reaction is thus,
Cl₂ + 2e⁻ -----------> 2Cl⁻
gain of electron is reduction
so the idea is;
loss of electron / oxidation / reducing agent
gain of electron / reduction / oxidizing agent
so with these, Cl₂ is obviously correct. ✔️✔️
Understand the difference b/w loss or gain of electron, and, increase and decrease in oxidation number. Chlorine had a decrease in oxidation number, from 0 to -1, while Iron had an increase in oxidation number from +2 to +3...
If u are confuse u can use this to remember
OIL RIG
Oxidation is loss
Reduction is gain
The oxidizing agent here is Cl2. Fe2+ donates an electron to Cl2 which is reduced to Cl-. Therefore Cl2 is responsible for oxidizing Fe2+ to Fe3+
The answer is definitely C....bcos d question talks about d ION which behaves like an oxidising agent...so ordinarily Fe2+ is a reducing agent which is oxidized to Fe3+, so from d reaction(reversible) the Fe3+ now act as oxidizing agent becos it can be reversely be reduced to Fe2+...so C is it
Hcl acid is used as test for both carbonate and sulphide eg Caco3 2 Hcl ----> cacl2 H2O CO2
PbS 2Hcl ------>Pbcl2 H2S
the liberation of CO2 and hydrogen sulphide are used to identify them respectively.
But in the test for sulphate barium chloride is added
the unkown acidified solution . White precipitate indicates the presence of sulphate ion
Conclusion
since the question said what can identify "just one of them" answer is A for barium chloride
The answer is correct. Oxidizing agents oxidation number reduce in the negative direction. From o to -1
actually i would'nt call it wrong but acccording to my opinion i thought it should be option D coz chlorine is been reduced to oxides Fe(+) which i guess Cl(-) is the oxidizing agent. thanks.....
Lol. My school is doing us crackers ooo 🤣🤣🤣.
C is correct. Cause oxidizing agents are atoms or elements that accepts electron to form ions.
In the equation. Fe²+ looses electron to Cl2 which makes Fe²+ the reducing agent. Cause reducing agent gives out electrons to be oxidized to their higher ion or to form a compound. Which makes Cl2 an oxidizing agent by making FeCl3...
The main explanation is, Fe²+ gives out electrons to Cl2
Reducing agents gives out electrons but becomes oxidized.
Oxidizing agents accepts electron but becomes reduced
as u know
Cathode= (reduction)
Anode= (oxidation)
from the question H2O + 2Fe2+Cl2
U can see
H+ and OH-
2fe2+ cl2-
it means cl2 goes to the anode and oxidation come to happen
as u know
Cathode= (reduction)
Anode= (oxidation)
from the question H2O + 2Fe2+Cl2
U can see
H+ and OH-
2fe2+ cl2-
it means cl2 goes to the anode and oxidation come to happen.
because fe2+ fe3+ is oxidation l.e reducing agent cl2 to 2cl- is reduction so oxidizing agent
the ansa z b bcos oxidizin agent z d 1 dat z been reducd(i.e 0 to -1) nd also cl2 z an oxidizin agent
