Three solutions contain carbonate, sulphate and sulphide ions respectively. One test that will identify just ONE of them completely is by addition to each of them of
barium chloride solution
dilute hydrochloric acid
lead nitrate solution
calcium chloride solution
sodium hydroxide solution
Explanation
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Discussions (58)
Hcl acid is used as test for both carbonate and sulphide eg Caco3 2 Hcl ----> cacl2 H2O CO2
PbS 2Hcl ------>Pbcl2 H2S
the liberation of CO2 and hydrogen sulphide are used to identify them respectively.
But in the test for sulphate barium chloride is added
the unkown acidified solution . White precipitate indicates the presence of sulphate ion
Conclusion
since the question said what can identify "just one of them" answer is A for barium chloride
There are two answers to this question from chem ababio
Both lead nitrate and hydrochloric acid will identify only one of the three.brief-- make research
The addition of **dilute hydrochloric acid** will identify the presence of **carbonate ions**. When dilute hydrochloric acid is added to a solution containing carbonate ions, it reacts to produce carbon dioxide gas. This gas can be confirmed by its ability to turn limewater milky. So, the correct answer is **B. dilute hydrochloric acid**. This test will not affect solutions containing sulphate or sulphide ions, thus identifying the carbonate ions completely.
u are all wrong both admin too....d correct ans is 'A' barium chloride.....barium chloride is a test for sulphate wich forms a white precipitate
After reading the comments, I'm becoming more confused. 😅
The correct answer is C !
Hcl acid is used as test for both carbonate and sulphide eg Caco3 2 Hcl ----> cacl2+H2O+CO2
PbS+2Hcl ------>Pbcl2+H2S
the liberation of CO2 and hydrogen sulphide are used to identify them respectively.
But in the test for sulphate barium chloride is added the unkown acidified solution . White precipitate indicates the presence of sulphate ion
Barium chloride reacts with all, two step I'm carbonate and sulphide.
C is very very correct
To identify the ions present in the solutions, the following tests can be used:
Carbonate ions (CO3^2-) can be identified by adding dilute hydrochloric acid (HCl), which will produce effervescence due to the release of carbon dioxide gas (CO2).
Sulphate ions (SO4^2-) can be identified by adding barium chloride solution (BaCl2), which will produce a white precipitate of barium sulphate (BaSO4).
Sulphide ions (S^2-) can be identified by adding lead nitrate solution (Pb(NO3)2), which will produce a black precipitate of lead sulphide (PbS).
Therefore, option C, adding lead nitrate solution, will identify just ONE of the ions completely, specifically the sulphide ions.
Greetings, The Myschool Team.
The correct answer is C(lead nitrate solution) and not A(barium chloride solution). This is apparent from the explanation officially provided.
1. Barium chloride solution also forms a white precipitate of BaCO3 with carbonates and also a white precipitate of BaS with sulphide ions. Thus, it cannot on its own identify any of the ions.
2. Dilute hydrochloric acid does give effervescence with carbonates(gas evolved is colourless and odourless), but it also gives effervescence with sulphides(gas evolved has a foul smell). This allows it to distinguish between carbonates, sulphides and even sulphates, which does not satisfy the demands of the question.
3. Lead nitrate solution gives a white precipitate with both carbonates and sulphates(which is included in the official explanation), but gives a black precipitate with sulphides. Thus, it cannot differentiate between carbonates and sulphates (both form white precipitates), but clearly distinguishes sulphides(black precipitates), thus fulfilling the demands of the question (identifying just one of the ions).
Thus, on the basis of the above, the correct answer is C (lead nitrate solution) and not A(barium chloride solution). Thank you.
admin pls help us recheck dis answers o.cos 4 dis question d correct answer is HCL i.e hydrogen chloride cos it react wit carbonate to give effervecence colourless gas which turns lime water milky nd also burn at minus 198 which serve as refridgrant.also react wit excess coke givin CO.gbam*
Let's consider **D. calcium chloride solution**.
Calcium chloride (CaCl₂) can be used to test for **sulphate ions (SO₄²⁻)** because calcium ions (Ca²⁺) will react with sulphate ions to form **calcium sulphate (CaSO₄)**, which is a white precipitate. However, this test is not unique to sulphate ions, as calcium ions can also form precipitates with carbonate ions (CaCO₃).
Here's what happens with each ion:
- **Carbonate ions (CO₃²⁻)**: Calcium chloride reacts with carbonate ions to form a white precipitate of calcium carbonate (CaCO₃).
\[
Ca^{2+} + CO₃^{2-} \rightarrow CaCO₃ \ (white \ precipitate)
\]
- **Sulphate ions (SO₄²⁻)**: Calcium chloride reacts with sulphate ions to form a white precipitate of calcium sulphate (CaSO₄), though it is sparingly soluble.
\[
Ca^{2+} + SO₄^{2-} \rightarrow CaSO₄ \ (white \ precipitate)
\]
- **Sulphide ions (S²⁻)**: Calcium chloride does not form a precipitate with sulphide ions under normal conditions.
So, while calcium chloride can help identify **carbonate** or **sulphate** ions based on the formation of precipitates, it cannot clearly differentiate one from the other. Therefore, **dilute hydrochloric acid (B)** is a better test for identifying carbonate ions alone.
