Consider the following exothermic reaction
2SO2(g) + O2(g) ↔ 2SO3(g)
If the temperature of the reaction is reduced from 800°C to 500°C, an no other change takes place, then
the reaction rate increases
concentration of SO3 decreases
concentration of SO3 increases
SO2 gas becomes unreactive
O3 gas becomes unreactive
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Here is an explanation:
If a reaction is endothermic increase in temp favour forward reaction and vise versa bt when its exothermic increase in temp favours backward reaction and vise versa
REF: New school chemistry
In exothermic reaction:Increase in temp of d system aids d formation of d reactant while decrease in temp aids d formation of d products .so d answer is option C
In exothermic reaction, the heat of production is less than the heat of reactant which makes change in temperature to be negative (ie /\H= -ve).
So in 2SO2 + O2 2SO3 (all gas), the reaction took place at the temperature of 800•c, now if the temperature of the system is reduced to 500•c, delta H will be new temperature minus old temperature (ie 500•c - 800•c = -300•c). Then the forward reaction will be favoured and more of SO3 will be produced
So SO3 will be concentrated in the system.
At equilibrum...d increase in temperature favours d products formed,while a decrease in temperature favours d backward reaction...here d temperature was given 2 hav reduced(800-500)..so it should favour d yield of so2 nt so3(product)...
increasing the temperature of a systerm in equilibrium shift the equilibrium position to the left,while decreasing it shift da equilibrium position 2 da left left favouring da backward reaction
Here is an explanation:
this is a reverisble rxn.that d rxn is exothermic means itis d forward rxn dat gives releases heat.if d temp. is reduced [800 to 600]d system will adjust itself in order to cancel d effect of d change.[le chatelier principle].d forward rxn dat gives out heat will b favoured.more SO3 produced.
It is option c because when one consider when is exected pressure on equlibrum,it favour lease volume an frm d ques it is so3 dat has d least mole so it concentration will increase
Bt wait ooo,wt abt a...if d reaction rate increases,doesn't dt mean dt d production of so3 increases??u r talking abt d concentration,prove it to me hw dt affect conc
c is the correct answer...in an exothermic rtn if the temp increases the equilibrium shifts to the right...meaning reactant will decrease and product will increase
Yea.bcos an increase in temp for exothermic increases d formation of products while d reverse is d case for endothermic
