Correct Answer: Option C

Explanation

Sulphuric acid (H\(_2\)SO\(_4\)) is a strong acid that fully dissociates in water, yielding two moles of hydrogen ions (H\(^+\)) for every one mole of acid, especially in dilute solutions.

      [ H\(^+\) ] =  2 X  [H\(_2\)SO\(_4\)]

                      = 2 X 0.06

  [ H\(^+\) ]     = 0.12 =  1.2 X 10\(^{-1}\) moldm\(^{-3}\)

To get the [OH\(^-\)], recall that the product of the hydrogen ion concentration, [H+] and the hydroxide ion concentration ([OH−]) in an aqueous solution at standard temperature is a constant, known as the ion product of water (Kw), which is approximately1.0 x10\(^{-14}\)mol\(^2\)/dm\(^6\).

    K\(_w\) =  [ H\(^+\) ] [OH\(^-\)]

      [OH\(^-\)] = \(\frac{K_w}{[H^+]}\)

                      = \(\frac{1.0 x10^{-14}}{0.12}\)

    [OH\(^-\)]   = 8.33 x 10\(^{-14}\)

There is an explanation video available below.

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