Calculate the time required to liberate 9g of Aluminium metal, when a current of 18A is passed through it.
(1F = 96500C , Al = 27)
Al\(^{3+}\) + 3e\(^-\) → Al
3e\(^-\) = 3F
3 F produced 27g of Al
3 x 96,500C produced 27g Al
(18 x t) C will produce 9g Al (Recall that Q = I x t)
By simple proportion,
\(\frac{3 x 96500}{18t}\) = \(\frac{27}{9}\)
t = \(\frac{9 x 3 x 96500}{18 x 27}\)
t = 5,361.11 seconds
Since the option is in minutes, we have to convert 5,361 seconds to minutes by dividing by 60 (60 sec = 1 min)
t = \(\frac{5361}{60}\)
t = 89.35 minutes
The correct answer is option B.
There is an explanation video available below.
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}