The relative molecular mass of an alkanoic acid with the empirical formula of CH\(_2\)O is
[ H = 1, C = 12, O = 16 ]
An alkanoic acid is a type of saturated carboxylic acid with the general molecular formula C\(_n\)H\(_{2n}\)O\(_2\).
Given: empirical formula is CH\(_2\)O.
Recall, (Empirical formula) x = Relative molecular mass, since the molecular formula is a whole-number multiple of the empirical formula, (CH\(_2\)O)?, which expands to C\(_x\)H\(_{2x}\)O\(_x\).
Equating the general formula for an alkanoic acid to the derived empirical formula general form, we find x = 2 for the oxygen atoms. Thus, the molecular formula is C\(_2\)H\(_4\)O\(_2\). i.e C\(_n\)H\(_{2n}\)O\(_2\) = C\(_x\)H\(_{2x}\)O\(_x\)
The relative molecular mass with the empirical formula CH\(_2\)O can be calculated using the following expression:
Relative Molecular Mass = (2×C) + (4×H) + (2×O)
Substituting the values:
Relative Molecular Mass = (2 x12) + (4 x 1) + (2 x16)
= 60
Relative Molecular Mass=24+4+32Relative Molecular Mass equals 24 plus 4 plus 32
Relative Molecular Mass=24+4+32
There is an explanation video available below.
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