The empirical mass of C\(_6\)H\(_{12}\)O\(_6\) is  [H =1, C = 12, O = 16]

The empirical mass of C\(_6\)H\(_{12}\)O\(_6\) is

[H =1, C = 12, O = 16]

Firstly, determine the empirical formula.

Molecular formula for the compound : C\(_6\)H\(_{12}\)O\(_6\)

To find the empirical formula, the subscripts of each element must be divided by their greatest common divisor, which is 6.

C\(_6\)H\(_{12}\)O\(_6\) → CH\(_2\)O

Empirical formula : CH\(_2\)O

Now, we can calculate the empirical mass of CH\(_2\)O = 12 + (1 x 2) + 16

= 30.

:. The correct answer is option D

There is an explanation video available below.

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