Correct Answer: Option A

Explanation

The reaction between 2-methylpropene and HCl is an electrophilic addition reaction that follows Markovnikov's rule. This rule states that in the addition of a hydrogen halide (HX) to an unsymmetrical alkene, the hydrogen atom (H) adds to the carbon atom of the double bond that already has more hydrogen atoms, and the halide atom (Cl) adds to the carbon atom with fewer hydrogen atoms. 

              CH\(_3\)C(CH\(_3\))=CH\(_2\)  +   HCl  →  CH\(_3\)C(CH\(_3\))Cl - CH\(_3\)

                 2-methylpropene                  2 -Chloro, 2-methylpentane

This results in the formation of a more stable tertiary carbocation intermediate, leading to the major product 2-chloro, 2-methylpropane.

There is an explanation video available below.

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