What is the molecular mass of an alkanoic acid, if 0.5 mole of the acid weighs 44g?

What is the molecular mass of an alkanoic acid, if 0.5 mole of the acid weighs 44g?

Given:

Number of moles, n = 0.5 mole

Mass of acid, m = 44 g

Molar mass of acid, M = ?

Recall that Number of moles, n = \(\frac{mass}{Molecular mass}\)

n = \(\frac{m}{M}\)

M = \(\frac{m}{n}\)

M = \(\frac{44}{0.5}\)

M = 88

:. The molecular mass of the alkanoic acid is 88 - option B

There is an explanation video available below.

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