What is the molecular mass of an alkanoic acid, if 0.5 mole of the acid weighs 44g?
Given:
Number of moles, n = 0.5 mole
Mass of acid, m = 44 g
Molar mass of acid, M = ?
Recall that Number of moles, n = \(\frac{mass}{Molecular mass}\)
n = \(\frac{m}{M}\)
M = \(\frac{m}{n}\)
M = \(\frac{44}{0.5}\)
M = 88
:. The molecular mass of the alkanoic acid is 88 - option B
There is an explanation video available below.
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}