NH\(_3\) \((_g\)) +  HCl\((_g\)) →   NH\(_4\)Cl \(_(g)\) In the reaction above, increase in pressure will

NH\(_3\) \((_g\)) + HCl\((_g\)) → NH\(_4\)Cl \(_(g)\) In the reaction above, increase in pressure will

Chemistry

JAMB 2025

NH\(_3\) \((_g\)) + HCl\((_g\)) → NH\(_4\)Cl \(_(g)\)

In the reaction above, increase in pressure will

A. lower the equilibrium constant
B. favour the product
C. favour the reactant
D. increase the equilibrium constant

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Correct Answer: Option B

Explanation

An increase in pressure will favour the forward reaction (production of NH\(_4\)Cl).

According to Le Chatelier's principle, increasing the pressure on a system at equilibrium will cause the equilibrium to shift in the direction that reduces the total number of moles of gas. In this reaction, the reactant side has two moles of gas (one NH\(_3\) and one HCl), while the product side has zero moles of gas (solid NH\(_4\)Cl). The system relieves the pressure by favoring the side with fewer gas molecules, thus promoting the formation of the solid product.

NH\(_3\) + HCl ⇌ NH\(_4\)Cl

An increase in pressure will favour the forward reaction (production of NH\(_4\)Cl).

There is an explanation video available below.

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