Given:
Concentration of OH = [OH\(^-\)] = 0.001 M
At 25\(^0\)C, pH + pOH = 14
Hence, to find pH of KOH, we need to find the pOH first, then substitute the value into the equation above.
Recall, pOH = - Log [OH\(^-\)]
= - Log [0.001]
= - ( - 3)
pOH = 3
pH + pOH = 14
pH + 3 = 14
pH = 14 - 3 = 11
;. pH = 11 - option A
There is an explanation video available below.
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