The percentage by mass of Oxygen in MgSO\(_4\).7H\(_2\)O is [ M\(_r\) of MgSO\(_4\).7H\(_2\)O = 246 ]
a
26.0%
b
45.5%
c
71.5%
d
84.0%
Explanation
Correct Option
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Youngboss_19
1 year ago
% Composition of O4 = molar mass of oxygen /
molar mass of MgSO4.7H20* 100%
64/246 *100
=26.02%.(A)
@ My School pls look into it because there's no option marked here .

