The product of the reaction between ethanol and excess acidified K\(_2\)Cr\(_2\)O\(_7\) is

a

CH\(_2\)=CH\(_2\)

b

CH\(_3\)OCH\(_3\)

c

CH\(_3\)COOH

d

CH\(_3\)CH\(_3\)

Download Offline App Ask a Question

Explanation

Correct Option
c

Video Explanation

No video available

Post your Contribution

Share:

Discussions (3)

001shedy
1 year ago

Ethanoic acid (CH₃COOH) or Acetic acid.

The reaction is an oxidation reaction, where ethanol (C₂H₅OH) is oxidized to ethanoic acid (CH₃COOH) by the acidified potassium dichromate (K₂Cr₂O₇) solution.

option C is correct

dahu
1 year ago

NO ANSWER

Quick Questions

Ask a Question
CO

ceoofwahala

20th June, 2026

Chemistry


2 comments

ASSAAS

20th June, 2026

English Language


5 comments

infinitehoaxx

21st May, 2026

Computer


4 comments