The oxidation number of Chromium in Na\(_2\)Cr\(_2\)O\(_7\) is 

GOG16

1 year ago

Option B is correct. MySchool please adress this problem and possibly give me my points.

001shedy

1 year ago

To solve the oxidation number of chromium in Na2Cr2O7:

1. Identify the oxidation numbers of the other elements:
- Na (sodium) has an oxidation number of +1.
- O (oxygen) has an oxidation number of -2.
2. Determine the total charge of the compound: Na2Cr2O7 is neutral, so the total charge is 0.
3. Set up an equation using the oxidation numbers:

2(+1) + 2x + 7(-2) = 0

Simplify the equation:

2 + 2x - 14 = 0

Combine like terms:

2x - 12 = 0

Add 12 to both sides:

2x = 12

Divide by 2:

x = 6

So, the oxidation number of chromium (Cr) in Na2Cr2O7 is +6.

option B is correct ✅