Correct Answer: Option C

Explanation

Oxidation state of S in  H\(_2\)S = 0

H = +1,                         (+1 X 2) + S = 0

                                       + 2 + S = 0

                                         S = - 2 ( from the reactant)

Already, from the equation, S is in solid form,as an element, therefore the oxidation state of elements in their free state is 0

The change in oxidation state of sulphur is from - 2 to 0 

There is an explanation video available below.

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