C\(_x\)H\(_y\)O + 5O\(_2\) → 4CO\(_2\) + 4H\(_2\)O
C\(_x\)H\(_y\)O in the equation is
C\(_x\)H\(_y\)O + 5O\(_2\) → 4CO\(_2\) + 4H\(_2\)O
On balancing the equation, we should have
X = 4 , y = 8 and O = 2 ⇒ C\(_4\)H\(_8\)O\(_2\)
Since 2 is a common factor to the three atoms, we can divide through by 2, considering the fact that that formula is not in the option.
We finally have C\(_2\)H\(_4\)O
There is an explanation video available below.
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