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C\(_x\)H\(_y\)O + 5O\(_2\)  →  4CO\(_2\)  +  4H\(_2\)O C\(_x\)H\(_y\)O in the equation is

Chemistry
JAMB 2024

C\(_x\)H\(_y\)O + 5O\(_2\)  →  4CO\(_2\)  +  4H\(_2\)O

C\(_x\)H\(_y\)O in the equation is

  • A. CH\(_2\)O
  • B. C\(_2\)H\(_6\)O
  • C. CH\(_4\)O
  • D. C\(_2\)H\(_4\)O
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Correct Answer: Option D
Explanation

C\(_x\)H\(_y\)O + 5O\(_2\)  →  4CO\(_2\)  +  4H\(_2\)O

On balancing the equation, we should have

X = 4 , y = 8  and O = 2  ⇒   C\(_4\)H\(_8\)O\(_2\)

Since 2 is a common factor to the three atoms, we can divide through by 2, considering the fact that that formula is not in the option.

We finally have  C\(_2\)H\(_4\)O

There is an explanation video available below.


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Explanation Video

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