How much of 5g of radioactive element whose half life is 50days remains after 200days?
There are several methods of solving this radioactivity problem. One of the easiest is:
\(\frac{Original mass}{2^n}\) = Residual mass
Where n = number of activity = \(\frac{exposure time}{half life}\)
Given:
Original mass = 5g, exposure time = 200 days , half life = 50 days, Residual mass = ?
Substituting all the given parameters appropriately, we have
n = \(\frac{200}{50}\)
n = 4
\(\frac{Original mass}{2^n}\) = Residual mass
\(\frac{5}{2^4}\) = Residual mass
\(\frac{5}{16}\) = Residual mass
Residual mass = 0.3125g = 0.31g
There is an explanation video available below.
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