CuO\(_s\) + H\(_2\)(\(_g\)) ⇌ Cu\(_s\) + H\(_2\)O(\(_g\))
In the equation above, the effect of increased pressure on the equilibrium position is that
a
the equilibrium is shifted to the left
b
the equilibrium is shifted to the right
c
there is no effect
d
more H\(_2\)\((g\)) is produced
Explanation
Correct Option
cVideo Explanation
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Odemosad
1 year ago
Option C is correct, since the number of moles of gases on both sides are equal, there'll be no effect.
