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An organic compound contains 53.1% Carbon, 6.2% Hydrogen, 12.4% Nitrogen, and 28.3% Oxygen by mass....

Chemistry
JAMB 2024

An organic compound contains 53.1% Carbon, 6.2% Hydrogen, 12.4% Nitrogen, and 28.3% Oxygen by mass. What is the molecular formula of the compound if its vapour density is 56.5?   [ C =12, H = 1, N = 14, O = 16]. 

  • A. C\(_5\)H\(_7\)NO\(_2\)
  • B. C\(_5\)H\(_6\)NO\(_2\)
  • C. C\(_3\)H\(_6\)NO\(_2\)
  • D. C\(_3\)H\(_7\)NO\(_2\)
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Correct Answer: Option A
Explanation

   C               H             N             O

\(\frac{53.1}{12}\)           \(\frac{6.2}{1}\)       \(\frac{12.4}{14}\)           \(\frac{28.3}{16}\)

\(\frac{4.425}{0.886}\)       \(\frac{6.2}{0.886}\)      \(\frac{0.886}{0.886}\)         \(\frac{1.769}{0.886}\)

   5       :        7     :         1      :        2

C\(_5\)         H\(_7\)         N              O\(_2\) -  Empirical formula

(Empirical formula) n = Molecular formula 

(C\(_5\)H\(_7\)NO\(_2\))n = 2 x vapour density

([12x5] + [1x7] + 14 + [16x2] ) n = 2 x 56.5

113n = 113 

 n = \(\frac{113}{113}\)

 n = 1

Therefore, the molecular formula is C\(_5\)H\(_7\)NO\(_2\) 

 

There is an explanation video available below.


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