The number of molecules of helium gas contained in 11.5g of the gas is
1.73 x 10\(^{23}\)
1.73 x 10\(^{22}\)
1.73 x 10\(^{24}\)
1.73 x 10\(^{21}\)
the answer is c
nawa OĆ š it actually easy
not enough data
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men failed it !
ceoofwahala
20th June, 2026
ASSAAS
infinitehoaxx
21st May, 2026
