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The number of molecules of helium gas contained in 11.5g of the gas is

Chemistry
JAMB 2024

The number of molecules of helium gas contained in 11.5g of the gas is

  • A. 1.73 x 10\(^{23}\)
  • B. 1.73 x 10\(^{22}\)
  • C. 1.73 x 10\(^{24}\)
  • D. 1.73 x 10\(^{21}\)
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Correct Answer: Option C
Explanation

To find the number of molecules, we'll use the formula:

Number of moles = \(\frac{Number of molecules}{Avogadro number}\)

But We were only given the mass of Helium = 11.5g , knowing the atomic mass or molar mass of He = 4 g/mol

Number of moles = \(\frac{mass}{molar mass}\) = \(\frac{11.5}{4}\) = 2.875 moles

Number of molecules = Number of moles x Avogadro number

                                   = 2.875 x 6.02 x 10\(^{23}\)

                                   = 17.3075 x 10\(^{23}\)

                                   = 1.73 x 10\(^{24}\)

There is an explanation video available below.


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Explanation Video

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